Procs

proc pullDown[T](x: var seq[T]; i, n: int) {.inline.}

move n items down 1; i.e. x[i..i+n-1] = x[i+1..i+n]   Source   Edit

proc pushUp[T](x: var seq[T]; i, n: int) {.inline.}

move n items up 1; i.e. x[i+1..i+n] = x[i..i+n-1]   Source   Edit